Base | Representation |
---|---|
bin | 11001111110101000010010… |
… | …101011011111111101111111 |
3 | 112222112200012201120121120201 |
4 | 121332220102223133331333 |
5 | 104433423302022314330 |
6 | 1043000012052424331 |
7 | 33031440144622600 |
oct | 3176502253377577 |
9 | 488480181517521 |
10 | 114255033401215 |
11 | 33450318806923 |
12 | 109934836180a7 |
13 | 4b9a284bb0795 |
14 | 202dd8a369da7 |
15 | d32080339eca |
hex | 67ea12adff7f |
114255033401215 has 48 divisors (see below), whose sum is σ = 161838522823680. Its totient is φ = 77197031795520.
The previous prime is 114255033401213. The next prime is 114255033401237. The reversal of 114255033401215 is 512104330552411.
It is not a de Polignac number, because 114255033401215 - 21 = 114255033401213 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (114255033401213) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 3491974 + ... + 15514636.
It is an arithmetic number, because the mean of its divisors is an integer number (3371635892160).
Almost surely, 2114255033401215 is an apocalyptic number.
114255033401215 is a deficient number, since it is larger than the sum of its proper divisors (47583489422465).
114255033401215 is a wasteful number, since it uses less digits than its factorization.
114255033401215 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12023252 (or 12023245 counting only the distinct ones).
The product of its (nonzero) digits is 72000, while the sum is 37.
Adding to 114255033401215 its reverse (512104330552411), we get a palindrome (626359363953626).
The spelling of 114255033401215 in words is "one hundred fourteen trillion, two hundred fifty-five billion, thirty-three million, four hundred one thousand, two hundred fifteen".
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