Base | Representation |
---|---|
bin | 11001111110101000010110… |
… | …110010011100011001010011 |
3 | 112222112200101112021120201101 |
4 | 121332220112302130121103 |
5 | 104433423422144033301 |
6 | 1043000022554045231 |
7 | 33031441642536505 |
oct | 3176502662343123 |
9 | 488480345246641 |
10 | 114255102330451 |
11 | 33450353706435 |
12 | 109934a2719817 |
13 | 4b9a296265b04 |
14 | 202dd9558dd75 |
15 | d32086403701 |
hex | 67ea16c9c653 |
114255102330451 has 2 divisors, whose sum is σ = 114255102330452. Its totient is φ = 114255102330450.
The previous prime is 114255102330403. The next prime is 114255102330503. The reversal of 114255102330451 is 154033201552411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114255102330451 - 221 = 114255100233299 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 114255102330451.
It is not a weakly prime, because it can be changed into another prime (114255102330751) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57127551165225 + 57127551165226.
It is an arithmetic number, because the mean of its divisors is an integer number (57127551165226).
Almost surely, 2114255102330451 is an apocalyptic number.
114255102330451 is a deficient number, since it is larger than the sum of its proper divisors (1).
114255102330451 is an equidigital number, since it uses as much as digits as its factorization.
114255102330451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72000, while the sum is 37.
Adding to 114255102330451 its reverse (154033201552411), we get a palindrome (268288303882862).
The spelling of 114255102330451 in words is "one hundred fourteen trillion, two hundred fifty-five billion, one hundred two million, three hundred thirty thousand, four hundred fifty-one".
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