Base | Representation |
---|---|
bin | 11001111111010011001110… |
… | …111010011011100110011011 |
3 | 112222201002020001100122122101 |
4 | 121333103032322123212123 |
5 | 104440202214110330201 |
6 | 1043033115212504231 |
7 | 33034661554631245 |
oct | 3177231672334633 |
9 | 488632201318571 |
10 | 114301141105051 |
11 | 3346892936918a |
12 | 109a03b0a7b077 |
13 | 4ba172243bc84 |
14 | 20322c1b81095 |
15 | d3337d131d01 |
hex | 67f4cee9b99b |
114301141105051 has 2 divisors, whose sum is σ = 114301141105052. Its totient is φ = 114301141105050.
The previous prime is 114301141104947. The next prime is 114301141105061. The reversal of 114301141105051 is 150501141103411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 114301141105051 - 219 = 114301140580763 is a prime.
It is not a weakly prime, because it can be changed into another prime (114301141105061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57150570552525 + 57150570552526.
It is an arithmetic number, because the mean of its divisors is an integer number (57150570552526).
Almost surely, 2114301141105051 is an apocalyptic number.
114301141105051 is a deficient number, since it is larger than the sum of its proper divisors (1).
114301141105051 is an equidigital number, since it uses as much as digits as its factorization.
114301141105051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1200, while the sum is 28.
Adding to 114301141105051 its reverse (150501141103411), we get a palindrome (264802282208462).
The spelling of 114301141105051 in words is "one hundred fourteen trillion, three hundred one billion, one hundred forty-one million, one hundred five thousand, fifty-one".
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