Base | Representation |
---|---|
bin | 110101001110100000… |
… | …0111101001101000101 |
3 | 101221001000001112100021 |
4 | 1222131000331031011 |
5 | 3333043134021201 |
6 | 124302115015141 |
7 | 11154355032034 |
oct | 1523500751505 |
9 | 357030045307 |
10 | 114303423301 |
11 | 445263367a1 |
12 | 1a19bb9a4b1 |
13 | aa17c47622 |
14 | 576495c71b |
15 | 2e8ed05ea1 |
hex | 1a9d03d345 |
114303423301 has 4 divisors (see below), whose sum is σ = 114306118272. Its totient is φ = 114300728332.
The previous prime is 114303423229. The next prime is 114303423323. The reversal of 114303423301 is 103324303411.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 114303423301 - 215 = 114303390533 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (114303423361) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1282831 + ... + 1369036.
It is an arithmetic number, because the mean of its divisors is an integer number (28576529568).
Almost surely, 2114303423301 is an apocalyptic number.
It is an amenable number.
114303423301 is a deficient number, since it is larger than the sum of its proper divisors (2694971).
114303423301 is an equidigital number, since it uses as much as digits as its factorization.
114303423301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2694970.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 114303423301 its reverse (103324303411), we get a palindrome (217627726712).
The spelling of 114303423301 in words is "one hundred fourteen billion, three hundred three million, four hundred twenty-three thousand, three hundred one".
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