Base | Representation |
---|---|
bin | 10101010010101100… |
… | …01011111111111011 |
3 | 1002111122122001211022 |
4 | 22221112023333323 |
5 | 141402330203121 |
6 | 5130144053055 |
7 | 553162515233 |
oct | 125126137773 |
9 | 32448561738 |
10 | 11431100411 |
11 | 4936615a25 |
12 | 227030418b |
13 | 1102337a53 |
14 | 7a624ccc3 |
15 | 46d847aab |
hex | 2a958bffb |
11431100411 has 2 divisors, whose sum is σ = 11431100412. Its totient is φ = 11431100410.
The previous prime is 11431100399. The next prime is 11431100497. The reversal of 11431100411 is 11400113411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11431100411 - 230 = 10357358587 is a prime.
It is a super-3 number, since 3×114311004113 (a number of 31 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 11431100411.
It is not a weakly prime, because it can be changed into another prime (11431100111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5715550205 + 5715550206.
It is an arithmetic number, because the mean of its divisors is an integer number (5715550206).
Almost surely, 211431100411 is an apocalyptic number.
11431100411 is a deficient number, since it is larger than the sum of its proper divisors (1).
11431100411 is an equidigital number, since it uses as much as digits as its factorization.
11431100411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 11431100411 its reverse (11400113411), we get a palindrome (22831213822).
The spelling of 11431100411 in words is "eleven billion, four hundred thirty-one million, one hundred thousand, four hundred eleven".
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