Base | Representation |
---|---|
bin | 11001111111011101011101… |
… | …100000001011100100001001 |
3 | 112222202010120102021222002100 |
4 | 121333131131200023210021 |
5 | 104440342212031100410 |
6 | 1043042133043224013 |
7 | 33035530660016523 |
oct | 3177353540134411 |
9 | 488663512258070 |
10 | 114312123300105 |
11 | 33472554545945 |
12 | 109a2556978009 |
13 | 4ba2782771343 |
14 | 2032a44538a13 |
15 | d337c23558c0 |
hex | 67f75d80b909 |
114312123300105 has 24 divisors (see below), whose sum is σ = 209796367469832. Its totient is φ = 57380203067904.
The previous prime is 114312123300097. The next prime is 114312123300149. The reversal of 114312123300105 is 501003321213411.
114312123300105 is a `hidden beast` number, since 1 + 1 + 4 + 312 + 1 + 2 + 330 + 0 + 10 + 5 = 666.
It can be written as a sum of positive squares in 4 ways, for example, as 1556777748681 + 112755345551424 = 1247709^2 + 10618632^2 .
It is not a de Polignac number, because 114312123300105 - 23 = 114312123300097 is a prime.
It is a super-2 number, since 2×1143121233001052 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 74713805314 + ... + 74713806843.
It is an arithmetic number, because the mean of its divisors is an integer number (8741515311243).
Almost surely, 2114312123300105 is an apocalyptic number.
114312123300105 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
114312123300105 is a deficient number, since it is larger than the sum of its proper divisors (95484244169727).
114312123300105 is a wasteful number, since it uses less digits than its factorization.
114312123300105 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 149427612185 (or 149427612182 counting only the distinct ones).
The product of its (nonzero) digits is 2160, while the sum is 27.
Adding to 114312123300105 its reverse (501003321213411), we get a palindrome (615315444513516).
The spelling of 114312123300105 in words is "one hundred fourteen trillion, three hundred twelve billion, one hundred twenty-three million, three hundred thousand, one hundred five".
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