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114312555101 = 787145251023
BaseRepresentation
bin110101001110110001…
…1110010101001011101
3101221001122020110211002
41222131203302221131
53333103003230401
6124303042440045
711154525454253
oct1523543625135
9357048213732
10114312555101
1144530503638
121a1a3063025
13aa19ac3c64
145765c585d3
152e90a0ba6b
hex1a9d8f2a5d

114312555101 has 4 divisors (see below), whose sum is σ = 114457806912. Its totient is φ = 114167303292.

The previous prime is 114312555089. The next prime is 114312555127. The reversal of 114312555101 is 101555213411.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 114312555101 - 230 = 113238813277 is a prime.

It is a super-2 number, since 2×1143125551012 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114312555131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 72624725 + ... + 72626298.

It is an arithmetic number, because the mean of its divisors is an integer number (28614451728).

Almost surely, 2114312555101 is an apocalyptic number.

It is an amenable number.

114312555101 is a deficient number, since it is larger than the sum of its proper divisors (145251811).

114312555101 is an equidigital number, since it uses as much as digits as its factorization.

114312555101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 145251810.

The product of its (nonzero) digits is 3000, while the sum is 29.

Adding to 114312555101 its reverse (101555213411), we get a palindrome (215867768512).

The spelling of 114312555101 in words is "one hundred fourteen billion, three hundred twelve million, five hundred fifty-five thousand, one hundred one".

Divisors: 1 787 145251023 114312555101