114315144013331 has 2 divisors, whose sum is σ = 114315144013332. Its totient is φ = 114315144013330.

The previous prime is 114315144013321. The next prime is 114315144013351. The reversal of 114315144013331 is 133310441513411.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 114315144013331 - 2¹⁸ = 114315143751187 is a prime.

It is a super-2 number, since 2×114315144013331² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 114315144013291 and 114315144013300.

It is not a weakly prime, because it can be changed into another prime (114315144013321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57157572006665 + 57157572006666.

It is an arithmetic number, because the mean of its divisors is an integer number (57157572006666).

Almost surely, 2^{114315144013331} is an apocalyptic number.

114315144013331 is a deficient number, since it is larger than the sum of its proper divisors (1).

114315144013331 is an equidigital number, since it uses as much as digits as its factorization.

114315144013331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 25920, while the sum is 35.

Adding to 114315144013331 its reverse (133310441513411), we get a palindrome (247625585526742).

The spelling of 114315144013331 in words is "one hundred fourteen trillion, three hundred fifteen billion, one hundred forty-four million, thirteen thousand, three hundred thirty-one".