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114319115190793 is a prime number
BaseRepresentation
bin11001111111100011111110…
…010000001000001000001001
3112222202210121200202210222201
4121333203332100020020021
5104441001021442101133
61043045250531520201
733036166150062502
oct3177437620101011
9488683550683881
10114319115190793
11334755122608a7
12109a3988459061
134ba3328198176
142033108d83ba9
15d33a810bbd7d
hex67f8fe408209

114319115190793 has 2 divisors, whose sum is σ = 114319115190794. Its totient is φ = 114319115190792.

The previous prime is 114319115190713. The next prime is 114319115190809. The reversal of 114319115190793 is 397091511913411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 76238515972089 + 38080599218704 = 8731467^2 + 6170948^2 .

It is a cyclic number.

It is not a de Polignac number, because 114319115190793 - 29 = 114319115190281 is a prime.

It is not a weakly prime, because it can be changed into another prime (114319115190713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57159557595396 + 57159557595397.

It is an arithmetic number, because the mean of its divisors is an integer number (57159557595397).

Almost surely, 2114319115190793 is an apocalyptic number.

It is an amenable number.

114319115190793 is a deficient number, since it is larger than the sum of its proper divisors (1).

114319115190793 is an equidigital number, since it uses as much as digits as its factorization.

114319115190793 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 918540, while the sum is 55.

The spelling of 114319115190793 in words is "one hundred fourteen trillion, three hundred nineteen billion, one hundred fifteen million, one hundred ninety thousand, seven hundred ninety-three".