Base | Representation |
---|---|
bin | 110101001111000001… |
… | …0010010110100101101 |
3 | 101221002012021201102101 |
4 | 1222132002102310231 |
5 | 3333112030114323 |
6 | 124303530055101 |
7 | 11154653436451 |
oct | 1523602226455 |
9 | 357065251371 |
10 | 114320551213 |
11 | 44534a751a0 |
12 | 1a1a587a491 |
13 | aa1b66369b |
14 | 5766d3a661 |
15 | 2e9158adad |
hex | 1a9e092d2d |
114320551213 has 4 divisors (see below), whose sum is σ = 124713328608. Its totient is φ = 103927773820.
The previous prime is 114320551171. The next prime is 114320551229. The reversal of 114320551213 is 312155023411.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 114320551213 - 217 = 114320420141 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (114320551283) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5196388681 + ... + 5196388702.
It is an arithmetic number, because the mean of its divisors is an integer number (31178332152).
Almost surely, 2114320551213 is an apocalyptic number.
It is an amenable number.
114320551213 is a deficient number, since it is larger than the sum of its proper divisors (10392777395).
114320551213 is a wasteful number, since it uses less digits than its factorization.
114320551213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10392777394.
The product of its (nonzero) digits is 3600, while the sum is 28.
Adding to 114320551213 its reverse (312155023411), we get a palindrome (426475574624).
The spelling of 114320551213 in words is "one hundred fourteen billion, three hundred twenty million, five hundred fifty-one thousand, two hundred thirteen".
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