Base | Representation |
---|---|
bin | 110101001111000001… |
… | …0010010110101110011 |
3 | 101221002012021201111222 |
4 | 1222132002102311303 |
5 | 3333112030120113 |
6 | 124303530055255 |
7 | 11154653436611 |
oct | 1523602226563 |
9 | 357065251458 |
10 | 114320551283 |
11 | 44534a75254 |
12 | 1a1a587a52b |
13 | aa1b663723 |
14 | 5766d3a6b1 |
15 | 2e9158ae08 |
hex | 1a9e092d73 |
114320551283 has 2 divisors, whose sum is σ = 114320551284. Its totient is φ = 114320551282.
The previous prime is 114320551271. The next prime is 114320551291. The reversal of 114320551283 is 382155023411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 114320551283 - 210 = 114320550259 is a prime.
It is not a weakly prime, because it can be changed into another prime (114320551783) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57160275641 + 57160275642.
It is an arithmetic number, because the mean of its divisors is an integer number (57160275642).
Almost surely, 2114320551283 is an apocalyptic number.
114320551283 is a deficient number, since it is larger than the sum of its proper divisors (1).
114320551283 is an equidigital number, since it uses as much as digits as its factorization.
114320551283 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 28800, while the sum is 35.
Adding to 114320551283 its reverse (382155023411), we get a palindrome (496475574694).
The spelling of 114320551283 in words is "one hundred fourteen billion, three hundred twenty million, five hundred fifty-one thousand, two hundred eighty-three".
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