1143212131 has 2 divisors, whose sum is σ = 1143212132. Its totient is φ = 1143212130.

The previous prime is 1143212099. The next prime is 1143212167. The reversal of 1143212131 is 1312123411.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1143212131 - 2⁵ = 1143212099 is a prime.

It is a super-2 number, since 2×1143212131² = 2613867952931122322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1143212099 and 1143212108.

It is not a weakly prime, because it can be changed into another prime (1143212831) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 571606065 + 571606066.

It is an arithmetic number, because the mean of its divisors is an integer number (571606066).

Almost surely, 2^1143212131 is an apocalyptic number.

1143212131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1143212131 is an equidigital number, since it uses as much as digits as its factorization.

1143212131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 144, while the sum is 19.

The square root of 1143212131 is about 33811.4201269334. The cubic root of 1143212131 is about 1045.6241567881.

Adding to 1143212131 its reverse (1312123411), we get a palindrome (2455335542).

The spelling of 1143212131 in words is "one billion, one hundred forty-three million, two hundred twelve thousand, one hundred thirty-one".