Base | Representation |
---|---|
bin | 11001111111100110000001… |
… | …000100101101000000001001 |
3 | 112222210000021122201020211212 |
4 | 121333212001010231000021 |
5 | 104441020020330331101 |
6 | 1043050252414302505 |
7 | 33036304430540423 |
oct | 3177460104550011 |
9 | 488700248636755 |
10 | 114321310011401 |
11 | 33476439173029 |
12 | 109a429b4b7a35 |
13 | 4ba35b7b0519c |
14 | 2033276673813 |
15 | d33b5db141bb |
hex | 67f98112d009 |
114321310011401 has 2 divisors, whose sum is σ = 114321310011402. Its totient is φ = 114321310011400.
The previous prime is 114321310011319. The next prime is 114321310011413. The reversal of 114321310011401 is 104110013123411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 87363417985600 + 26957892025801 = 9346840^2 + 5192099^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-114321310011401 is a prime.
It is not a weakly prime, because it can be changed into another prime (114321310011451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57160655005700 + 57160655005701.
It is an arithmetic number, because the mean of its divisors is an integer number (57160655005701).
Almost surely, 2114321310011401 is an apocalyptic number.
It is an amenable number.
114321310011401 is a deficient number, since it is larger than the sum of its proper divisors (1).
114321310011401 is an equidigital number, since it uses as much as digits as its factorization.
114321310011401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 288, while the sum is 23.
Adding to 114321310011401 its reverse (104110013123411), we get a palindrome (218431323134812).
The spelling of 114321310011401 in words is "one hundred fourteen trillion, three hundred twenty-one billion, three hundred ten million, eleven thousand, four hundred one".
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