Base | Representation |
---|---|
bin | 1010011001011100010011… |
… | …1000111001001110001110 |
3 | 1111110220112110022201222201 |
4 | 2212113010320321032032 |
5 | 2444301132033122223 |
6 | 40151515122032114 |
7 | 2256643565025625 |
oct | 246270470711616 |
9 | 44426473281881 |
10 | 11432211223438 |
11 | 3708412220225 |
12 | 13477804a863a |
13 | 64c08c288505 |
14 | 2b74717026bc |
15 | 14c5a0db3ead |
hex | a65c4e3938e |
11432211223438 has 4 divisors (see below), whose sum is σ = 17148316835160. Its totient is φ = 5716105611718.
The previous prime is 11432211223369. The next prime is 11432211223439. The reversal of 11432211223438 is 83432211223411.
11432211223438 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 11432211223397 and 11432211223406.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11432211223439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2858052805858 + ... + 2858052805861.
It is an arithmetic number, because the mean of its divisors is an integer number (4287079208790).
Almost surely, 211432211223438 is an apocalyptic number.
11432211223438 is a deficient number, since it is larger than the sum of its proper divisors (5716105611722).
11432211223438 is an equidigital number, since it uses as much as digits as its factorization.
11432211223438 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5716105611721.
The product of its digits is 55296, while the sum is 37.
Adding to 11432211223438 its reverse (83432211223411), we get a palindrome (94864422446849).
The spelling of 11432211223438 in words is "eleven trillion, four hundred thirty-two billion, two hundred eleven million, two hundred twenty-three thousand, four hundred thirty-eight".
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