Base | Representation |
---|---|
bin | 10000101000101110011… |
… | …111111110001110010001 |
3 | 11001021220110110012202101 |
4 | 100220232133332032101 |
5 | 122212324301342001 |
6 | 2233110423320401 |
7 | 145411405565152 |
oct | 20505637761621 |
9 | 4037813405671 |
10 | 1143241434001 |
11 | 400933a92407 |
12 | 1656992b0101 |
13 | 83a65575804 |
14 | 3d494367929 |
15 | 1eb11d1ca01 |
hex | 10a2e7fe391 |
1143241434001 has 2 divisors, whose sum is σ = 1143241434002. Its totient is φ = 1143241434000.
The previous prime is 1143241433987. The next prime is 1143241434011. The reversal of 1143241434001 is 1004341423411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 915464326401 + 227777107600 = 956799^2 + 477260^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1143241434001 is a prime.
It is not a weakly prime, because it can be changed into another prime (1143241434011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 571620717000 + 571620717001.
It is an arithmetic number, because the mean of its divisors is an integer number (571620717001).
Almost surely, 21143241434001 is an apocalyptic number.
It is an amenable number.
1143241434001 is a deficient number, since it is larger than the sum of its proper divisors (1).
1143241434001 is an equidigital number, since it uses as much as digits as its factorization.
1143241434001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 1143241434001 its reverse (1004341423411), we get a palindrome (2147582857412).
The spelling of 1143241434001 in words is "one trillion, one hundred forty-three billion, two hundred forty-one million, four hundred thirty-four thousand, one".
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