Base | Representation |
---|---|
bin | 10101010010111011… |
… | …10100010001111011 |
3 | 1002111210101200022101 |
4 | 22221131310101323 |
5 | 141403333203121 |
6 | 5130255004231 |
7 | 553215515155 |
oct | 125135642173 |
9 | 32453350271 |
10 | 11433100411 |
11 | 4937761617 |
12 | 2270b09677 |
13 | 1102888195 |
14 | 7a660dad5 |
15 | 46dae0491 |
hex | 2a977447b |
11433100411 has 2 divisors, whose sum is σ = 11433100412. Its totient is φ = 11433100410.
The previous prime is 11433100339. The next prime is 11433100433. The reversal of 11433100411 is 11400133411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11433100411 - 211 = 11433098363 is a prime.
It is not a weakly prime, because it can be changed into another prime (11433103411) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5716550205 + 5716550206.
It is an arithmetic number, because the mean of its divisors is an integer number (5716550206).
Almost surely, 211433100411 is an apocalyptic number.
11433100411 is a deficient number, since it is larger than the sum of its proper divisors (1).
11433100411 is an equidigital number, since it uses as much as digits as its factorization.
11433100411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 11433100411 its reverse (11400133411), we get a palindrome (22833233822).
The spelling of 11433100411 in words is "eleven billion, four hundred thirty-three million, one hundred thousand, four hundred eleven".
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