1143310481 has 2 divisors, whose sum is σ = 1143310482. Its totient is φ = 1143310480.

The previous prime is 1143310459. The next prime is 1143310489. The reversal of 1143310481 is 1840133411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 919059856 + 224250625 = 30316^2 + 14975^2 .

It is a cyclic number.

It is not a de Polignac number, because 1143310481 - 2³⁰ = 69568657 is a prime.

It is a super-3 number, since 3×1143310481³ (a number of 28 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 1143310481.

It is not a weakly prime, because it can be changed into another prime (1143310489) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 571655240 + 571655241.

It is an arithmetic number, because the mean of its divisors is an integer number (571655241).

Almost surely, 2^1143310481 is an apocalyptic number.

It is an amenable number.

1143310481 is a deficient number, since it is larger than the sum of its proper divisors (1).

1143310481 is an equidigital number, since it uses as much as digits as its factorization.

1143310481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 26.

The square root of 1143310481 is about 33812.8744859114. The cubic root of 1143310481 is about 1045.6541407792.

Adding to 1143310481 its reverse (1840133411), we get a palindrome (2983443892).

The spelling of 1143310481 in words is "one billion, one hundred forty-three million, three hundred ten thousand, four hundred eighty-one".