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114331131330114 = 2319055188555019
BaseRepresentation
bin11001111111101111001010…
…011110000011111001000010
3112222210221122010020221022210
4121333233022132003321002
5104441200124110030424
61043054555135242550
733040103005425606
oct3177571236037102
9488727563227283
10114331131330114
113347a619036156
12109a6180679456
134ba44c1790a8a
142033928ba3506
15d34035e79729
hex67fbca783e42

114331131330114 has 8 divisors (see below), whose sum is σ = 228662262660240. Its totient is φ = 38110377110036.

The previous prime is 114331131330107. The next prime is 114331131330149. The reversal of 114331131330114 is 411033131133411.

It is a sphenic number, since it is the product of 3 distinct primes.

114331131330114 is an admirable number.

It is a Curzon number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9527594277504 + ... + 9527594277515.

It is an arithmetic number, because the mean of its divisors is an integer number (28582782832530).

Almost surely, 2114331131330114 is an apocalyptic number.

114331131330114 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

114331131330114 is a wasteful number, since it uses less digits than its factorization.

114331131330114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19055188555024.

The product of its (nonzero) digits is 3888, while the sum is 30.

Adding to 114331131330114 its reverse (411033131133411), we get a palindrome (525364262463525).

The spelling of 114331131330114 in words is "one hundred fourteen trillion, three hundred thirty-one billion, one hundred thirty-one million, three hundred thirty thousand, one hundred fourteen".

Divisors: 1 2 3 6 19055188555019 38110377110038 57165565665057 114331131330114