Base | Representation |
---|---|
bin | 10101010010111100… |
… | …01101000010101001 |
3 | 1002111210120211102202 |
4 | 22221132031002221 |
5 | 141403344424313 |
6 | 5130301105545 |
7 | 553216416644 |
oct | 125136150251 |
9 | 32453524382 |
10 | 11433201833 |
11 | 4937820839 |
12 | 2270b582b5 |
13 | 11028c23b1 |
14 | 7a6638a5b |
15 | 46db10558 |
hex | 2a978d0a9 |
11433201833 has 2 divisors, whose sum is σ = 11433201834. Its totient is φ = 11433201832.
The previous prime is 11433201763. The next prime is 11433201839. The reversal of 11433201833 is 33810233411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8766202384 + 2666999449 = 93628^2 + 51643^2 .
It is a cyclic number.
It is not a de Polignac number, because 11433201833 - 218 = 11432939689 is a prime.
It is a super-2 number, since 2×114332018332 (a number of 21 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 11433201796 and 11433201805.
It is not a weakly prime, because it can be changed into another prime (11433201839) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5716600916 + 5716600917.
It is an arithmetic number, because the mean of its divisors is an integer number (5716600917).
Almost surely, 211433201833 is an apocalyptic number.
It is an amenable number.
11433201833 is a deficient number, since it is larger than the sum of its proper divisors (1).
11433201833 is an equidigital number, since it uses as much as digits as its factorization.
11433201833 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 29.
The spelling of 11433201833 in words is "eleven billion, four hundred thirty-three million, two hundred one thousand, eight hundred thirty-three".
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