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114332022113 is a prime number
BaseRepresentation
bin110101001111010111…
…0000011010101100001
3101221002222212111112112
41222132232003111201
53333122444201423
6124305020005105
711155153103351
oct1523656032541
9357088774475
10114332022113
114454049a481
121a1a9690795
13aa20b4b8ba
145768684b61
152e925a4a78
hex1a9eb83561

114332022113 has 2 divisors, whose sum is σ = 114332022114. Its totient is φ = 114332022112.

The previous prime is 114332022089. The next prime is 114332022127. The reversal of 114332022113 is 311220233411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 109788183649 + 4543838464 = 331343^2 + 67408^2 .

It is a cyclic number.

It is not a de Polignac number, because 114332022113 - 214 = 114332005729 is a prime.

It is a super-2 number, since 2×1143320221132 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (114332022163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57166011056 + 57166011057.

It is an arithmetic number, because the mean of its divisors is an integer number (57166011057).

Almost surely, 2114332022113 is an apocalyptic number.

It is an amenable number.

114332022113 is a deficient number, since it is larger than the sum of its proper divisors (1).

114332022113 is an equidigital number, since it uses as much as digits as its factorization.

114332022113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 114332022113 its reverse (311220233411), we get a palindrome (425552255524).

The spelling of 114332022113 in words is "one hundred fourteen billion, three hundred thirty-two million, twenty-two thousand, one hundred thirteen".