Base | Representation |
---|---|
bin | 11001111111110000000100… |
… | …010001111100101011111011 |
3 | 112222211001010201022010111211 |
4 | 121333300010101330223323 |
5 | 104441204120403432103 |
6 | 1043055235303503551 |
7 | 33040136023446154 |
oct | 3177600421745373 |
9 | 488731121263454 |
10 | 114332101233403 |
11 | 3347aa76572919 |
12 | 109a63b1457bb7 |
13 | 4ba46176c0c51 |
14 | 20339bb91892b |
15 | d340911b336d |
hex | 67fc0447cafb |
114332101233403 has 2 divisors, whose sum is σ = 114332101233404. Its totient is φ = 114332101233402.
The previous prime is 114332101233397. The next prime is 114332101233431. The reversal of 114332101233403 is 304332101233411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114332101233403 - 237 = 114194662279931 is a prime.
It is a super-2 number, since 2×1143321012334032 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (114332101233433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57166050616701 + 57166050616702.
It is an arithmetic number, because the mean of its divisors is an integer number (57166050616702).
Almost surely, 2114332101233403 is an apocalyptic number.
114332101233403 is a deficient number, since it is larger than the sum of its proper divisors (1).
114332101233403 is an equidigital number, since it uses as much as digits as its factorization.
114332101233403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 114332101233403 its reverse (304332101233411), we get a palindrome (418664202466814).
The spelling of 114332101233403 in words is "one hundred fourteen trillion, three hundred thirty-two billion, one hundred one million, two hundred thirty-three thousand, four hundred three".
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