Base | Representation |
---|---|
bin | 11001111111110000010001… |
… | …100001100000000001100011 |
3 | 112222211001201012101002011002 |
4 | 121333300101201200001203 |
5 | 104441210044243222430 |
6 | 1043055313321542215 |
7 | 33040144362114302 |
oct | 3177602141400143 |
9 | 488731635332132 |
10 | 114332323414115 |
11 | 3348007aa25544 |
12 | 109a645394496b |
13 | 4ba4651743121 |
14 | 20339dd232439 |
15 | d340a594e845 |
hex | 67fc11860063 |
114332323414115 has 8 divisors (see below), whose sum is σ = 137213567726928. Its totient is φ = 91456005644640.
The previous prime is 114332323414103. The next prime is 114332323414117. The reversal of 114332323414115 is 511414323233411.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a de Polignac number, because none of the positive numbers 2k-114332323414115 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (114332323414117) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1231584776 + ... + 1231677605.
It is an arithmetic number, because the mean of its divisors is an integer number (17151695965866).
Almost surely, 2114332323414115 is an apocalyptic number.
114332323414115 is a deficient number, since it is larger than the sum of its proper divisors (22881244312813).
114332323414115 is an equidigital number, since it uses as much as digits as its factorization.
114332323414115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2463271669.
The product of its digits is 103680, while the sum is 38.
Adding to 114332323414115 its reverse (511414323233411), we get a palindrome (625746646647526).
The spelling of 114332323414115 in words is "one hundred fourteen trillion, three hundred thirty-two billion, three hundred twenty-three million, four hundred fourteen thousand, one hundred fifteen".
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