114332323414117 has 2 divisors, whose sum is σ = 114332323414118. Its totient is φ = 114332323414116.

The previous prime is 114332323414103. The next prime is 114332323414121. The reversal of 114332323414117 is 711414323233411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 67335252109636 + 46997071304481 = 8205806^2 + 6855441^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-114332323414117 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 114332323414117.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114332323414147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57166161707058 + 57166161707059.

It is an arithmetic number, because the mean of its divisors is an integer number (57166161707059).

Almost surely, 2^{114332323414117} is an apocalyptic number.

It is an amenable number.

114332323414117 is a deficient number, since it is larger than the sum of its proper divisors (1).

114332323414117 is an equidigital number, since it uses as much as digits as its factorization.

114332323414117 is an evil number, because the sum of its binary digits is even.

The product of its digits is 145152, while the sum is 40.

Adding to 114332323414117 its reverse (711414323233411), we get a palindrome (825746646647528).

The spelling of 114332323414117 in words is "one hundred fourteen trillion, three hundred thirty-two billion, three hundred twenty-three million, four hundred fourteen thousand, one hundred seventeen".