1143340969 has 2 divisors, whose sum is σ = 1143340970. Its totient is φ = 1143340968.

The previous prime is 1143340943. The next prime is 1143340993. The reversal of 1143340969 is 9690433411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 926898025 + 216442944 = 30445^2 + 14712^2 .

It is an emirp because it is prime and its reverse (9690433411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1143340969 - 2⁵ = 1143340937 is a prime.

It is a super-2 number, since 2×1143340969² = 2614457142787717922, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1143340909) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 571670484 + 571670485.

It is an arithmetic number, because the mean of its divisors is an integer number (571670485).

Almost surely, 2^1143340969 is an apocalyptic number.

It is an amenable number.

1143340969 is a deficient number, since it is larger than the sum of its proper divisors (1).

1143340969 is an equidigital number, since it uses as much as digits as its factorization.

1143340969 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 69984, while the sum is 40.

The square root of 1143340969 is about 33813.3253170995. The cubic root of 1143340969 is about 1045.6634353148.

The spelling of 1143340969 in words is "one billion, one hundred forty-three million, three hundred forty thousand, nine hundred sixty-nine".