114338993 has 2 divisors, whose sum is σ = 114338994. Its totient is φ = 114338992.

The previous prime is 114338977. The next prime is 114339007. The reversal of 114338993 is 399833411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 62599744 + 51739249 = 7912^2 + 7193^2 .

It is a cyclic number.

It is not a de Polignac number, because 114338993 - 2⁴ = 114338977 is a prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 114338993.

It is not a weakly prime, because it can be changed into another prime (114335993) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57169496 + 57169497.

It is an arithmetic number, because the mean of its divisors is an integer number (57169497).

Almost surely, 2^114338993 is an apocalyptic number.

It is an amenable number.

114338993 is a deficient number, since it is larger than the sum of its proper divisors (1).

114338993 is an equidigital number, since it uses as much as digits as its factorization.

114338993 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 69984, while the sum is 41.

The square root of 114338993 is about 10692.9412698284. The cubic root of 114338993 is about 485.3609004719.

The spelling of 114338993 in words is "one hundred fourteen million, three hundred thirty-eight thousand, nine hundred ninety-three".