1143412022 has 4 divisors (see below), whose sum is σ = 1715118036. Its totient is φ = 571706010.

The previous prime is 1143412013. The next prime is 1143412031. The reversal of 1143412022 is 2202143411.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (1143412013) and next prime (1143412031).

It is a junction number, because it is equal to n+sod(n) for n = 1143411985 and 1143412003.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 285853004 + ... + 285853007.

It is an arithmetic number, because the mean of its divisors is an integer number (428779509).

Almost surely, 2^1143412022 is an apocalyptic number.

1143412022 is a deficient number, since it is larger than the sum of its proper divisors (571706014).

1143412022 is an equidigital number, since it uses as much as digits as its factorization.

1143412022 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 571706013.

The product of its (nonzero) digits is 384, while the sum is 20.

The square root of 1143412022 is about 33814.3759664436. The cubic root of 1143412022 is about 1045.6850958072.

Adding to 1143412022 its reverse (2202143411), we get a palindrome (3345555433).

The spelling of 1143412022 in words is "one billion, one hundred forty-three million, four hundred twelve thousand, twenty-two".