11434243252413 has 4 divisors (see below), whose sum is σ = 15245657669888. Its totient is φ = 7622828834940.

The previous prime is 11434243252373. The next prime is 11434243252433. The reversal of 11434243252413 is 31425234243411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 11434243252413 - 2¹² = 11434243248317 is a prime.

It is a super-3 number, since 3×11434243252413³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11434243252433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1905707208733 + ... + 1905707208738.

It is an arithmetic number, because the mean of its divisors is an integer number (3811414417472).

Almost surely, 2^{11434243252413} is an apocalyptic number.

It is an amenable number.

11434243252413 is a deficient number, since it is larger than the sum of its proper divisors (3811414417475).

11434243252413 is an equidigital number, since it uses as much as digits as its factorization.

11434243252413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3811414417474.

The product of its digits is 276480, while the sum is 39.

Adding to 11434243252413 its reverse (31425234243411), we get a palindrome (42859477495824).

The spelling of 11434243252413 in words is "eleven trillion, four hundred thirty-four billion, two hundred forty-three million, two hundred fifty-two thousand, four hundred thirteen".