Base | Representation |
---|---|
bin | 1010011001100011111000… |
… | …0000011101000010111101 |
3 | 1111111002210001221022002102 |
4 | 2212120332000131002331 |
5 | 2444314312232421232 |
6 | 40152452511234445 |
7 | 2260045130661461 |
oct | 246307600350275 |
9 | 44432701838072 |
10 | 11434243248317 |
11 | 370926525062a |
12 | 1348048b18a25 |
13 | 64c3242663b6 |
14 | 2b75c55364a1 |
15 | 14c66e4a0662 |
hex | a663e01d0bd |
11434243248317 has 2 divisors, whose sum is σ = 11434243248318. Its totient is φ = 11434243248316.
The previous prime is 11434243248287. The next prime is 11434243248341. The reversal of 11434243248317 is 71384234243411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10631160218116 + 803083030201 = 3260546^2 + 896149^2 .
It is a cyclic number.
It is not a de Polignac number, because 11434243248317 - 222 = 11434239054013 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11434243248217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5717121624158 + 5717121624159.
It is an arithmetic number, because the mean of its divisors is an integer number (5717121624159).
Almost surely, 211434243248317 is an apocalyptic number.
It is an amenable number.
11434243248317 is a deficient number, since it is larger than the sum of its proper divisors (1).
11434243248317 is an equidigital number, since it uses as much as digits as its factorization.
11434243248317 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1548288, while the sum is 47.
The spelling of 11434243248317 in words is "eleven trillion, four hundred thirty-four billion, two hundred forty-three million, two hundred forty-eight thousand, three hundred seventeen".
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