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11434340131 = 176716076247
BaseRepresentation
bin10101010011000101…
…00010111100100011
31002111212201122212221
422221202202330203
5141404142341011
65130341331511
7553232200414
oct125142427443
932455648787
1011434340131
114938428a85
122271406b97
131102c00546
147a685380b
1546dc87971
hex2a98a2f23

11434340131 has 16 divisors (see below), whose sum is σ = 12297263616. Its totient is φ = 10592816256.

The previous prime is 11434340117. The next prime is 11434340143. The reversal of 11434340131 is 13104343411.

It is a happy number.

It is a cyclic number.

It is not a de Polignac number, because 11434340131 - 221 = 11432242979 is a prime.

It is a super-2 number, since 2×114343401312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11434340096 and 11434340105.

It is not an unprimeable number, because it can be changed into a prime (11434340101) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1827250 + ... + 1833496.

It is an arithmetic number, because the mean of its divisors is an integer number (768578976).

Almost surely, 211434340131 is an apocalyptic number.

11434340131 is a deficient number, since it is larger than the sum of its proper divisors (862923485).

11434340131 is a wasteful number, since it uses less digits than its factorization.

11434340131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7938.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 11434340131 its reverse (13104343411), we get a palindrome (24538683542).

The spelling of 11434340131 in words is "eleven billion, four hundred thirty-four million, three hundred forty thousand, one hundred thirty-one".

Divisors: 1 17 67 1139 1607 6247 27319 106199 107669 418549 1830373 7115333 10038929 170661793 672608243 11434340131