Base | Representation |
---|---|
bin | 1010011001100100011110… |
… | …0010000001101010001001 |
3 | 1111111010012012121202112012 |
4 | 2212121013202001222021 |
5 | 2444320124134401402 |
6 | 40152520420225305 |
7 | 2260052111140154 |
oct | 246310742015211 |
9 | 44433165552465 |
10 | 11434403043977 |
11 | 3709337473461 |
12 | 134809253b235 |
13 | 64c34b3b4b44 |
14 | 2b75dc850c9b |
15 | 14c67d517452 |
hex | a6647881a89 |
11434403043977 has 2 divisors, whose sum is σ = 11434403043978. Its totient is φ = 11434403043976.
The previous prime is 11434403043911. The next prime is 11434403044219. The reversal of 11434403043977 is 77934030443411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10255135188496 + 1179267855481 = 3202364^2 + 1085941^2 .
It is a cyclic number.
It is not a de Polignac number, because 11434403043977 - 234 = 11417223174793 is a prime.
It is a super-2 number, since 2×114344030439772 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11434403043907) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5717201521988 + 5717201521989.
It is an arithmetic number, because the mean of its divisors is an integer number (5717201521989).
Almost surely, 211434403043977 is an apocalyptic number.
It is an amenable number.
11434403043977 is a deficient number, since it is larger than the sum of its proper divisors (1).
11434403043977 is an equidigital number, since it uses as much as digits as its factorization.
11434403043977 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3048192, while the sum is 50.
The spelling of 11434403043977 in words is "eleven trillion, four hundred thirty-four billion, four hundred three million, forty-three thousand, nine hundred seventy-seven".
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