Base | Representation |
---|---|
bin | 1010011001100100100111… |
… | …1110110000100000111011 |
3 | 1111111010022001221011110012 |
4 | 2212121021332300200323 |
5 | 2444320220144132423 |
6 | 40152524445012135 |
7 | 2260053120311432 |
oct | 246311176604073 |
9 | 44433261834405 |
10 | 11434444130363 |
11 | 3709358686251 |
12 | 13480a425404b |
13 | 64c356a6c007 |
14 | 2b76040a8119 |
15 | 14c681e31078 |
hex | a6649fb083b |
11434444130363 has 2 divisors, whose sum is σ = 11434444130364. Its totient is φ = 11434444130362.
The previous prime is 11434444130311. The next prime is 11434444130399. The reversal of 11434444130363 is 36303144443411.
11434444130363 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11434444130363 - 236 = 11365724653627 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11434444130363.
It is not a weakly prime, because it can be changed into another prime (11434444135363) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5717222065181 + 5717222065182.
It is an arithmetic number, because the mean of its divisors is an integer number (5717222065182).
Almost surely, 211434444130363 is an apocalyptic number.
11434444130363 is a deficient number, since it is larger than the sum of its proper divisors (1).
11434444130363 is an equidigital number, since it uses as much as digits as its factorization.
11434444130363 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 497664, while the sum is 41.
Adding to 11434444130363 its reverse (36303144443411), we get a palindrome (47737588573774).
The spelling of 11434444130363 in words is "eleven trillion, four hundred thirty-four billion, four hundred forty-four million, one hundred thirty thousand, three hundred sixty-three".
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