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114354041 is a prime number
BaseRepresentation
bin1101101000011…
…10011101111001
321222011210020212
412310032131321
5213233312131
615203000505
72555664464
oct664163571
9258153225
10114354041
115960597a
1232369135
131a8cb119
141128a2db
15a08ca2b
hex6d0e779

114354041 has 2 divisors, whose sum is σ = 114354042. Its totient is φ = 114354040.

The previous prime is 114354029. The next prime is 114354089. The reversal of 114354041 is 140453411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 110334016 + 4020025 = 10504^2 + 2005^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-114354041 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 114353998 and 114354016.

It is not a weakly prime, because it can be changed into another prime (114354341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57177020 + 57177021.

It is an arithmetic number, because the mean of its divisors is an integer number (57177021).

Almost surely, 2114354041 is an apocalyptic number.

It is an amenable number.

114354041 is a deficient number, since it is larger than the sum of its proper divisors (1).

114354041 is an equidigital number, since it uses as much as digits as its factorization.

114354041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 960, while the sum is 23.

The square root of 114354041 is about 10693.6448884372. The cubic root of 114354041 is about 485.3821921014.

The spelling of 114354041 in words is "one hundred fourteen million, three hundred fifty-four thousand, forty-one".