Search a number
-
+
114401300111 = 783211393187
BaseRepresentation
bin110101010001011011…
…0010100111010001111
3101221021211020012002022
41222202312110322033
53333243213100421
6124315532520355
711156654002130
oct1524266247217
9357254205068
10114401300111
114457660801a
121a2089200bb
13aa322c68b7
145773959c87
152e986db7ab
hex1aa2d94e8f

114401300111 has 16 divisors (see below), whose sum is σ = 132383618304. Its totient is φ = 96829945344.

The previous prime is 114401300071. The next prime is 114401300119. The reversal of 114401300111 is 111003104411.

It is a cyclic number.

It is not a de Polignac number, because 114401300111 - 214 = 114401283727 is a prime.

It is a super-2 number, since 2×1144013001112 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 114401300111.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114401300119) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1181060 + ... + 1274246.

It is an arithmetic number, because the mean of its divisors is an integer number (8273976144).

Almost surely, 2114401300111 is an apocalyptic number.

114401300111 is a deficient number, since it is larger than the sum of its proper divisors (17982318193).

114401300111 is an equidigital number, since it uses as much as digits as its factorization.

114401300111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 95390.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 114401300111 its reverse (111003104411), we get a palindrome (225404404522).

The spelling of 114401300111 in words is "one hundred fourteen billion, four hundred one million, three hundred thousand, one hundred eleven".

Divisors: 1 7 83 581 2113 14791 93187 175379 652309 1227653 7734521 54141647 196904131 1378328917 16343042873 114401300111