114403433 has 2 divisors, whose sum is σ = 114403434. Its totient is φ = 114403432.

The previous prime is 114403411. The next prime is 114403441. The reversal of 114403433 is 334304411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 98942809 + 15460624 = 9947^2 + 3932^2 .

It is a cyclic number.

It is not a de Polignac number, because 114403433 - 2⁶ = 114403369 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 114403399 and 114403408.

It is not a weakly prime, because it can be changed into another prime (114405433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57201716 + 57201717.

It is an arithmetic number, because the mean of its divisors is an integer number (57201717).

Almost surely, 2^114403433 is an apocalyptic number.

It is an amenable number.

114403433 is a deficient number, since it is larger than the sum of its proper divisors (1).

114403433 is an equidigital number, since it uses as much as digits as its factorization.

114403433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 23.

The square root of 114403433 is about 10695.9540481436. The cubic root of 114403433 is about 485.4520644214.

Adding to 114403433 its reverse (334304411), we get a palindrome (448707844).

The spelling of 114403433 in words is "one hundred fourteen million, four hundred three thousand, four hundred thirty-three".