11440412133 has 4 divisors (see below), whose sum is σ = 15253882848. Its totient is φ = 7626941420.

The previous prime is 11440412131. The next prime is 11440412141. The reversal of 11440412133 is 33121404411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11440412133 - 2¹ = 11440412131 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11440412131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1906735353 + ... + 1906735358.

It is an arithmetic number, because the mean of its divisors is an integer number (3813470712).

Almost surely, 2^11440412133 is an apocalyptic number.

It is an amenable number.

11440412133 is a deficient number, since it is larger than the sum of its proper divisors (3813470715).

11440412133 is an equidigital number, since it uses as much as digits as its factorization.

11440412133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3813470714.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 11440412133 its reverse (33121404411), we get a palindrome (44561816544).

The spelling of 11440412133 in words is "eleven billion, four hundred forty million, four hundred twelve thousand, one hundred thirty-three".