Base | Representation |
---|---|
bin | 10101010011111000… |
… | …11101001101111101 |
3 | 1002112100111202010221 |
4 | 22221330131031331 |
5 | 141412412214123 |
6 | 5131143101341 |
7 | 553344010114 |
oct | 125174351575 |
9 | 32470452127 |
10 | 11441132413 |
11 | 4941248137 |
12 | 2273741851 |
13 | 110443b049 |
14 | 7a7700c7b |
15 | 46e67a25d |
hex | 2a9f1d37d |
11441132413 has 4 divisors (see below), whose sum is σ = 12114140220. Its totient is φ = 10768124608.
The previous prime is 11441132401. The next prime is 11441132429. The reversal of 11441132413 is 31423114411.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 9780814404 + 1660318009 = 98898^2 + 40747^2 .
It is a cyclic number.
It is not a de Polignac number, because 11441132413 - 233 = 2851197821 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11441132453) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 336503878 + ... + 336503911.
It is an arithmetic number, because the mean of its divisors is an integer number (3028535055).
Almost surely, 211441132413 is an apocalyptic number.
It is an amenable number.
11441132413 is a deficient number, since it is larger than the sum of its proper divisors (673007807).
11441132413 is an equidigital number, since it uses as much as digits as its factorization.
11441132413 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 673007806.
The product of its digits is 1152, while the sum is 25.
Adding to 11441132413 its reverse (31423114411), we get a palindrome (42864246824).
The spelling of 11441132413 in words is "eleven billion, four hundred forty-one million, one hundred thirty-two thousand, four hundred thirteen".
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