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114412132513513 is a prime number
BaseRepresentation
bin11010000000111010100110…
…100001000011011011101001
3120000002200201020021101202101
4122000322212201003123221
5104444012021410413023
61043200112535533401
733046001205220342
oct3200724641033351
9500080636241671
10114412132513513
1133500a050a412a
12109b9a0782a261
134bac0301585b3
1420378108b70c9
15d361c72b01ad
hex680ea68436e9

114412132513513 has 2 divisors, whose sum is σ = 114412132513514. Its totient is φ = 114412132513512.

The previous prime is 114412132513451. The next prime is 114412132513543. The reversal of 114412132513513 is 315315231214411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 82556177397849 + 31855955115664 = 9086043^2 + 5644108^2 .

It is a cyclic number.

It is not a de Polignac number, because 114412132513513 - 233 = 114403542578921 is a prime.

It is not a weakly prime, because it can be changed into another prime (114412132513543) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57206066256756 + 57206066256757.

It is an arithmetic number, because the mean of its divisors is an integer number (57206066256757).

Almost surely, 2114412132513513 is an apocalyptic number.

It is an amenable number.

114412132513513 is a deficient number, since it is larger than the sum of its proper divisors (1).

114412132513513 is an equidigital number, since it uses as much as digits as its factorization.

114412132513513 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 43200, while the sum is 37.

Adding to 114412132513513 its reverse (315315231214411), we get a palindrome (429727363727924).

The spelling of 114412132513513 in words is "one hundred fourteen trillion, four hundred twelve billion, one hundred thirty-two million, five hundred thirteen thousand, five hundred thirteen".