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114422096250937 is a prime number
BaseRepresentation
bin11010000001000011111000…
…011001101100100000111001
3120000010122102121210200222101
4122001003320121230200321
5104444142423120012222
61043204441345223401
733046503132461446
oct3201037031544071
9500118377720871
10114422096250937
11335051583a0572
12109bb928631b61
134bacc5a48a407
1420380b7cba9cd
15d365abda8927
hex6810f866c839

114422096250937 has 2 divisors, whose sum is σ = 114422096250938. Its totient is φ = 114422096250936.

The previous prime is 114422096250871. The next prime is 114422096250953. The reversal of 114422096250937 is 739052690224411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 73907394557481 + 40514701693456 = 8596941^2 + 6365116^2 .

It is an emirp because it is prime and its reverse (739052690224411) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-114422096250937 is a prime.

It is a super-2 number, since 2×1144220962509372 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (114422096250967) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57211048125468 + 57211048125469.

It is an arithmetic number, because the mean of its divisors is an integer number (57211048125469).

Almost surely, 2114422096250937 is an apocalyptic number.

It is an amenable number.

114422096250937 is a deficient number, since it is larger than the sum of its proper divisors (1).

114422096250937 is an equidigital number, since it uses as much as digits as its factorization.

114422096250937 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6531840, while the sum is 55.

The spelling of 114422096250937 in words is "one hundred fourteen trillion, four hundred twenty-two billion, ninety-six million, two hundred fifty thousand, nine hundred thirty-seven".