Base | Representation |
---|---|
bin | 10000101001101110010… |
… | …001010001100111111011 |
3 | 11001101200000122012201201 |
4 | 100221232101101213323 |
5 | 122222022144320011 |
6 | 2233404522555031 |
7 | 145450046521354 |
oct | 20515621214773 |
9 | 4041600565651 |
10 | 1144311323131 |
11 | 401332a009a9 |
12 | 165937668a77 |
13 | 83ba6112bc2 |
14 | 3d5564a8d2b |
15 | 1eb75c06cc1 |
hex | 10a6e4519fb |
1144311323131 has 2 divisors, whose sum is σ = 1144311323132. Its totient is φ = 1144311323130.
The previous prime is 1144311323081. The next prime is 1144311323149. The reversal of 1144311323131 is 1313231134411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1144311323131 - 215 = 1144311290363 is a prime.
It is a super-2 number, since 2×11443113231312 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1144311323131.
It is not a weakly prime, because it can be changed into another prime (1144311323161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 572155661565 + 572155661566.
It is an arithmetic number, because the mean of its divisors is an integer number (572155661566).
Almost surely, 21144311323131 is an apocalyptic number.
1144311323131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1144311323131 is an equidigital number, since it uses as much as digits as its factorization.
1144311323131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2592, while the sum is 28.
Adding to 1144311323131 its reverse (1313231134411), we get a palindrome (2457542457542).
The spelling of 1144311323131 in words is "one trillion, one hundred forty-four billion, three hundred eleven million, three hundred twenty-three thousand, one hundred thirty-one".
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