114433143130301 has 4 divisors (see below), whose sum is σ = 118379113583100. Its totient is φ = 110487172677504.

The previous prime is 114433143130291. The next prime is 114433143130337. The reversal of 114433143130301 is 103031341334411.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 70683517207801 + 43749625922500 = 8407349^2 + 6614350^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-114433143130301 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114433143130351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1972985226356 + ... + 1972985226413.

It is an arithmetic number, because the mean of its divisors is an integer number (29594778395775).

Almost surely, 2^{114433143130301} is an apocalyptic number.

It is an amenable number.

114433143130301 is a deficient number, since it is larger than the sum of its proper divisors (3945970452799).

114433143130301 is an equidigital number, since it uses as much as digits as its factorization.

114433143130301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3945970452798.

The product of its (nonzero) digits is 15552, while the sum is 32.

Adding to 114433143130301 its reverse (103031341334411), we get a palindrome (217464484464712).

The spelling of 114433143130301 in words is "one hundred fourteen trillion, four hundred thirty-three billion, one hundred forty-three million, one hundred thirty thousand, three hundred one".