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1144334013001 = 4326612418907
BaseRepresentation
bin10000101001101111100…
…111110101001001001001
311001101201121022222101021
4100221233213311021021
5122222044001404001
62233411053152441
7145450443422524
oct20515747651111
94041647288337
101144334013001
11401344799163
1216594318b721
1383baaa2876a
143d5594d3bbb
151eb77bd9ba1
hex10a6f9f5249

1144334013001 has 4 divisors (see below), whose sum is σ = 1170946431952. Its totient is φ = 1117721594052.

The previous prime is 1144334012891. The next prime is 1144334013019. The reversal of 1144334013001 is 1003104334411.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1144334013001 - 225 = 1144300458569 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1144334013091) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13306209411 + ... + 13306209496.

It is an arithmetic number, because the mean of its divisors is an integer number (292736607988).

Almost surely, 21144334013001 is an apocalyptic number.

It is an amenable number.

1144334013001 is a deficient number, since it is larger than the sum of its proper divisors (26612418951).

1144334013001 is an equidigital number, since it uses as much as digits as its factorization.

1144334013001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26612418950.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1144334013001 its reverse (1003104334411), we get a palindrome (2147438347412).

The spelling of 1144334013001 in words is "one trillion, one hundred forty-four billion, three hundred thirty-four million, thirteen thousand, one".

Divisors: 1 43 26612418907 1144334013001