114433461130 has 8 divisors (see below), whose sum is σ = 205980230052. Its totient is φ = 45773384448.

The previous prime is 114433461113. The next prime is 114433461143. The reversal of 114433461130 is 31164334411.

It can be written as a sum of positive squares in 2 ways, for example, as 104469229089 + 9964232041 = 323217^2 + 99821^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 114433461092 and 114433461101.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5721673047 + ... + 5721673066.

Almost surely, 2^114433461130 is an apocalyptic number.

114433461130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

114433461130 is a deficient number, since it is larger than the sum of its proper divisors (91546768922).

114433461130 is a wasteful number, since it uses less digits than its factorization.

114433461130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11443346120.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 114433461130 its reverse (31164334411), we get a palindrome (145597795541).

The spelling of 114433461130 in words is "one hundred fourteen billion, four hundred thirty-three million, four hundred sixty-one thousand, one hundred thirty".