11443401331 has 4 divisors (see below), whose sum is σ = 11444301792. Its totient is φ = 11442500872.

The previous prime is 11443401269. The next prime is 11443401353. The reversal of 11443401331 is 13310434411.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13310434411 = 6689 ⋅1989899.

It is a cyclic number.

It is not a de Polignac number, because 11443401331 - 2²⁷ = 11309183603 is a prime.

It is a super-2 number, since 2×11443401331² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11443401296 and 11443401305.

It is not an unprimeable number, because it can be changed into a prime (11443401731) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 430891 + ... + 456676.

It is an arithmetic number, because the mean of its divisors is an integer number (2861075448).

Almost surely, 2^11443401331 is an apocalyptic number.

11443401331 is a deficient number, since it is larger than the sum of its proper divisors (900461).

11443401331 is an equidigital number, since it uses as much as digits as its factorization.

11443401331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 900460.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 11443401331 its reverse (13310434411), we get a palindrome (24753835742).

The spelling of 11443401331 in words is "eleven billion, four hundred forty-three million, four hundred one thousand, three hundred thirty-one".