Base | Representation |
---|---|
bin | 10101010100001010… |
… | …01111001010010011 |
3 | 1002112111211200111202 |
4 | 22222011033022103 |
5 | 141414004343011 |
6 | 5131304301415 |
7 | 553402404503 |
oct | 125205171223 |
9 | 32474750452 |
10 | 11443434131 |
11 | 494257a488 |
12 | 227447186b |
13 | 1104a658cc |
14 | 7a7b3da03 |
15 | 46e98223b |
hex | 2aa14f293 |
11443434131 has 2 divisors, whose sum is σ = 11443434132. Its totient is φ = 11443434130.
The previous prime is 11443434127. The next prime is 11443434137. The reversal of 11443434131 is 13143434411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11443434131 - 22 = 11443434127 is a prime.
It is a super-2 number, since 2×114434341312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11443434094 and 11443434103.
It is not a weakly prime, because it can be changed into another prime (11443434137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5721717065 + 5721717066.
It is an arithmetic number, because the mean of its divisors is an integer number (5721717066).
Almost surely, 211443434131 is an apocalyptic number.
11443434131 is a deficient number, since it is larger than the sum of its proper divisors (1).
11443434131 is an equidigital number, since it uses as much as digits as its factorization.
11443434131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6912, while the sum is 29.
Adding to 11443434131 its reverse (13143434411), we get a palindrome (24586868542).
The spelling of 11443434131 in words is "eleven billion, four hundred forty-three million, four hundred thirty-four thousand, one hundred thirty-one".
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