Base | Representation |
---|---|
bin | 10000101001110000001… |
… | …111000100111101111001 |
3 | 11001101202022200200110022 |
4 | 100221300033010331321 |
5 | 122222104120121213 |
6 | 2233412101500225 |
7 | 145450630033124 |
oct | 20516017047571 |
9 | 4041668620408 |
10 | 1144344301433 |
11 | 40134a585aa3 |
12 | 165946711675 |
13 | 83bacbbb6a8 |
14 | 3d55aa113bb |
15 | 1eb78a6d308 |
hex | 10a703c4f79 |
1144344301433 has 2 divisors, whose sum is σ = 1144344301434. Its totient is φ = 1144344301432.
The previous prime is 1144344301423. The next prime is 1144344301469. The reversal of 1144344301433 is 3341034434411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 748340914489 + 396003386944 = 865067^2 + 629288^2 .
It is a cyclic number.
It is not a de Polignac number, because 1144344301433 - 216 = 1144344235897 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1144344301393 and 1144344301402.
It is not a weakly prime, because it can be changed into another prime (1144344301423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 572172150716 + 572172150717.
It is an arithmetic number, because the mean of its divisors is an integer number (572172150717).
Almost surely, 21144344301433 is an apocalyptic number.
It is an amenable number.
1144344301433 is a deficient number, since it is larger than the sum of its proper divisors (1).
1144344301433 is an equidigital number, since it uses as much as digits as its factorization.
1144344301433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 82944, while the sum is 35.
Adding to 1144344301433 its reverse (3341034434411), we get a palindrome (4485378735844).
The spelling of 1144344301433 in words is "one trillion, one hundred forty-four billion, three hundred forty-four million, three hundred one thousand, four hundred thirty-three".
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