Base | Representation |
---|---|
bin | 11010000001001111111100… |
… | …001011100011001011101011 |
3 | 120000011212212000022121211011 |
4 | 122001033330023203023223 |
5 | 104444400432401202301 |
6 | 1043214422252244351 |
7 | 33050442040311526 |
oct | 3201177413431353 |
9 | 500155760277734 |
10 | 114435044553451 |
11 | 3350a6a2375926 |
12 | 10a02340a706b7 |
13 | 4bb1241c2b18b |
14 | 2038985829bbd |
15 | d36ab89e7a51 |
hex | 6813fc2e32eb |
114435044553451 has 2 divisors, whose sum is σ = 114435044553452. Its totient is φ = 114435044553450.
The previous prime is 114435044553439. The next prime is 114435044553469. The reversal of 114435044553451 is 154355440534411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114435044553451 - 211 = 114435044551403 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 114435044553395 and 114435044553404.
It is not a weakly prime, because it can be changed into another prime (114435044553481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57217522276725 + 57217522276726.
It is an arithmetic number, because the mean of its divisors is an integer number (57217522276726).
Almost surely, 2114435044553451 is an apocalyptic number.
114435044553451 is a deficient number, since it is larger than the sum of its proper divisors (1).
114435044553451 is an equidigital number, since it uses as much as digits as its factorization.
114435044553451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5760000, while the sum is 49.
The spelling of 114435044553451 in words is "one hundred fourteen trillion, four hundred thirty-five billion, forty-four million, five hundred fifty-three thousand, four hundred fifty-one".
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