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1144401313241 = 1423804217367
BaseRepresentation
bin10000101001110011101…
…000100011110111011001
311001101220021222011221202
4100221303220203313121
5122222213214010431
62233421455443545
7145452221443244
oct20516350436731
94041807864852
101144401313241
1140137978589a
121659618265b5
1383bbb9604a4
143d56441225b
151eb7da808cb
hex10a73a23dd9

1144401313241 has 4 divisors (see below), whose sum is σ = 1145205532032. Its totient is φ = 1143597094452.

The previous prime is 1144401313189. The next prime is 1144401313283. The reversal of 1144401313241 is 1423131044411.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1144401313241 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1144401313291) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 402107261 + ... + 402110106.

It is an arithmetic number, because the mean of its divisors is an integer number (286301383008).

Almost surely, 21144401313241 is an apocalyptic number.

It is an amenable number.

1144401313241 is a deficient number, since it is larger than the sum of its proper divisors (804218791).

1144401313241 is an equidigital number, since it uses as much as digits as its factorization.

1144401313241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 804218790.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 1144401313241 its reverse (1423131044411), we get a palindrome (2567532357652).

The spelling of 1144401313241 in words is "one trillion, one hundred forty-four billion, four hundred one million, three hundred thirteen thousand, two hundred forty-one".

Divisors: 1 1423 804217367 1144401313241