Base | Representation |
---|---|
bin | 10000101001110011101… |
… | …000100011111000000011 |
3 | 11001101220021222012000022 |
4 | 100221303220203320003 |
5 | 122222213214011113 |
6 | 2233421455444055 |
7 | 145452221443334 |
oct | 20516350437003 |
9 | 4041807865008 |
10 | 1144401313283 |
11 | 401379785928 |
12 | 16596182662b |
13 | 83bbb960507 |
14 | 3d56441228b |
15 | 1eb7da80908 |
hex | 10a73a23e03 |
1144401313283 has 2 divisors, whose sum is σ = 1144401313284. Its totient is φ = 1144401313282.
The previous prime is 1144401313189. The next prime is 1144401313291. The reversal of 1144401313283 is 3823131044411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1144401313283 - 212 = 1144401309187 is a prime.
It is a super-2 number, since 2×11444013132832 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1144401315283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 572200656641 + 572200656642.
It is an arithmetic number, because the mean of its divisors is an integer number (572200656642).
Almost surely, 21144401313283 is an apocalyptic number.
1144401313283 is a deficient number, since it is larger than the sum of its proper divisors (1).
1144401313283 is an equidigital number, since it uses as much as digits as its factorization.
1144401313283 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27648, while the sum is 35.
Adding to 1144401313283 its reverse (3823131044411), we get a palindrome (4967532357694).
The spelling of 1144401313283 in words is "one trillion, one hundred forty-four billion, four hundred one million, three hundred thirteen thousand, two hundred eighty-three".
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