Base | Representation |
---|---|
bin | 1010011010001000011000… |
… | …1101000010111010110000 |
3 | 1111112001002010121121000110 |
4 | 2212202012031002322300 |
5 | 2444444400334141222 |
6 | 40201153233021320 |
7 | 2260543042524135 |
oct | 246420615027260 |
9 | 44461063547013 |
10 | 11444044443312 |
11 | 3712434819488 |
12 | 1349b233b4840 |
13 | 6502269c7470 |
14 | 2b7c7510858c |
15 | 14ca44b8d30c |
hex | a6886342eb0 |
11444044443312 has 80 divisors (see below), whose sum is σ = 31891071340800. Its totient is φ = 3515365790976.
The previous prime is 11444044443301. The next prime is 11444044443379. The reversal of 11444044443312 is 21334444044411.
It is a Harshad number since it is a multiple of its sum of digits (39).
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14934918 + ... + 15682469.
It is an arithmetic number, because the mean of its divisors is an integer number (398638391760).
Almost surely, 211444044443312 is an apocalyptic number.
11444044443312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
11444044443312 is an abundant number, since it is smaller than the sum of its proper divisors (20447026897488).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11444044443312 is a wasteful number, since it uses less digits than its factorization.
11444044443312 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30618010 (or 30618004 counting only the distinct ones).
The product of its (nonzero) digits is 294912, while the sum is 39.
Adding to 11444044443312 its reverse (21334444044411), we get a palindrome (32778488487723).
The spelling of 11444044443312 in words is "eleven trillion, four hundred forty-four billion, forty-four million, four hundred forty-three thousand, three hundred twelve".
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