Base | Representation |
---|---|
bin | 110101010100011000… |
… | …1010010110101110011 |
3 | 101221112202011101120102 |
4 | 1222220301102311303 |
5 | 3333444131103321 |
6 | 124333442103015 |
7 | 11162301263102 |
oct | 1525061226563 |
9 | 357482141512 |
10 | 114500644211 |
11 | 446176a0788 |
12 | 1a23604aa6b |
13 | aa49a6a9a5 |
14 | 5782c1a039 |
15 | 2ea22b1c0b |
hex | 1aa8c52d73 |
114500644211 has 2 divisors, whose sum is σ = 114500644212. Its totient is φ = 114500644210.
The previous prime is 114500644157. The next prime is 114500644231. The reversal of 114500644211 is 112446005411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 114500644211 - 26 = 114500644147 is a prime.
It is a super-3 number, since 3×1145006442113 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (114500644231) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57250322105 + 57250322106.
It is an arithmetic number, because the mean of its divisors is an integer number (57250322106).
Almost surely, 2114500644211 is an apocalyptic number.
114500644211 is a deficient number, since it is larger than the sum of its proper divisors (1).
114500644211 is an equidigital number, since it uses as much as digits as its factorization.
114500644211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3840, while the sum is 29.
Adding to 114500644211 its reverse (112446005411), we get a palindrome (226946649622).
The spelling of 114500644211 in words is "one hundred fourteen billion, five hundred million, six hundred forty-four thousand, two hundred eleven".
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